1. One of the following is 3 to 8 decoder
(a) 74X130
(b) 74X119
(c) 74X36
(d) 74X138
2. 10011 input in seven segment decodes as output.
(a) 1111101
(b) 1011001
(c) 1111001
(d) 1111000
3. is a priority encoder
(a) 74 × 146
(b) 74 × 148
(c) 74 × 144
(d) 74 × 48
4. The purpose of conv std logic vector (j, n) in VHDL coding of 74 × 148, 8 input priority encoder is to convert
integer j to
(a) std logic vector
(b) std ulogic
(c) real
(d) std logic
5. contains inverting buffer
(a) 74543
(b) 74540
(c) 74504
(d) 74542
6. For 74 × 151, input 0001 produces
(a) D5&D61
(b) D1&D11
(c) D5&D51
(d) D1&D21
7. is 9 bit parity generator.
(a) 74 × 138
(b) 74 × 280
(c) 74 × 86
(d) 74 × 153
8. is 4 bit comparator.
(a) 74 × 280
(b) 74 × 153
(c) 74 × 85
(d) 74 × 138
9. is quadruple 2 input XOR gate.
(a) 74 × 153
(b) 74 × 280
(c) 74 × 86
(d) 74 × 138
10. Borrow out in full sub tractor VHDL code is
(a) bout < = ( not X and bin) nor ( not X nand y) or ( bin and Y);
(b) bout < = ( not X n and bin) or ( not X and y) nor ( bin and Y);
(c) bout < = ( not X and bin) nor ( not X and y) or ( bin nand Y);
(d) bout < = ( not X and bin) or ( not X and Y) or ( bin and Y);
11. For 74 x 382, if S2 S1 S0 =110, then F is
(a) A1B1
(b) A · B
(c) A _ B
(d) A1 _ B
12. A combinational fixed point to floating point encoder consists of
(a) 74 x 280,two 74 x 138
(b) one 74 x 148, three 74 x 154
(c) one 74 x 148, two 74 x 154, 74 x 251
(d) two 74 x 154, 74 x 251
13. 74LS74 characteristic equation is
(a) Q_ = D
(b) Q_ = S + R1.Q
(c) Q_ = EN.D + EN1.Q
(d) Q_ = J.Q0 + K L.Q
14. If is negative, the circuit don’t work.
(a) set up time margin
(b) tcomb(min)
(c) Hold time margin
(d) tffpd(min)
15. consider Bus holder circuit in 3.3V CMOS LVC. Specify a maximum over ride cutoff
(a) 200 micro A
(b) 500 μ A
(c) 300micro A
(d) 100 mA
16. GAL22V10 has tCF =
(a) 5 or 20
(b) 12 or 3.5
(c) 13 or 2.5
(d) 10 or 1.5
17. In 74 × 299, bits shifted right if
(a) S1 =1 , SD =1
(b) S1 =1, SD =0
(c) S1 =0 , SD =1
(d) S1 =0 , SD =0
18. MTBF (tr) is
(a) [log(tr/_)]/[T1.f.a]
(b) [exp(tr/_)]/[T0.f.a]
(c) [erfc(tr/_)]/[T0.f.a2]
(d) [exp(tr)][T0.f ]
19. EPROM (CMOS Technology) Write cycle is
(a) 50 - 100 μs /byte
(b) 70 - 500 μs /byte
(c) 10 - 50 μs/byte
(d) 100 - 500 μs /byte
20. In SRAMs output buffer is automatically disabled whenever is asserted ,even if OE L is asserted.
(a) CLR H
(b) WE L
(c) CLR L
(d) WE H
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